(x^2-9)(x^2+2x-3)=0

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Solution for (x^2-9)(x^2+2x-3)=0 equation:


Simplifying
(x2 + -9)(x2 + 2x + -3) = 0

Reorder the terms:
(-9 + x2)(x2 + 2x + -3) = 0

Reorder the terms:
(-9 + x2)(-3 + 2x + x2) = 0

Multiply (-9 + x2) * (-3 + 2x + x2)
(-9(-3 + 2x + x2) + x2(-3 + 2x + x2)) = 0
((-3 * -9 + 2x * -9 + x2 * -9) + x2(-3 + 2x + x2)) = 0
((27 + -18x + -9x2) + x2(-3 + 2x + x2)) = 0
(27 + -18x + -9x2 + (-3 * x2 + 2x * x2 + x2 * x2)) = 0
(27 + -18x + -9x2 + (-3x2 + 2x3 + x4)) = 0

Combine like terms: -9x2 + -3x2 = -12x2
(27 + -18x + -12x2 + 2x3 + x4) = 0

Solving
27 + -18x + -12x2 + 2x3 + x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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